SOLUTION: The square of the sum of two consecutive integers is 529. What are the integers? x = 1st integer x + 1 = 2nd integer (x + (x + 1))2 = 529 2x2 = 528 x2 = 264 x = 16.24...

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The square of the sum of two consecutive integers is 529. What are the integers? x = 1st integer x + 1 = 2nd integer (x + (x + 1))2 = 529 2x2 = 528 x2 = 264 x = 16.24...      Log On


   

Question 135912: The square of the sum of two consecutive integers is 529. What are the integers?
x = 1st integer
x + 1 = 2nd integer
(x + (x + 1))2 = 529
2x2 = 528
x2 = 264
x = 16.24....
Answer should be 11 and 12.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
(x+(x+1))^2 does NOT equal 2x^2+1

(2x+1)(2x+1) __ FOILing __ 4x^2+4x+1=529

subtracting 1 and dividing by 4 __ x^2+x=132

subtracting 132 __ x^2+x-132=0 __ factoring __ (x+12)(x-11)=0

so x=-12 and x=11