SOLUTION: I need help with a homework question,please. It's on solving rational equations. I am suppose to use Least Common Denominatoe to find the solution, so, I'd really appreciate the h

Algebra ->  Rational-functions -> SOLUTION: I need help with a homework question,please. It's on solving rational equations. I am suppose to use Least Common Denominatoe to find the solution, so, I'd really appreciate the h      Log On


   

Question 135704This question is from textbook McDougal Littell Algebra 2
: I need help with a homework question,please. It's on solving rational equations.
I am suppose to use Least Common Denominatoe to find the solution, so, I'd really appreciate the help!
3x%2F%28x%2B1%29+%2B+6%2F2X+=+7%2Fx This question is from textbook McDougal Littell Algebra 2

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given : %283x%29%2F%28x%2B1%29+%2B+6%2F%282X%29+=+7%2Fx+
%283x%29%2F%28x%2B1%29+%2B+6%2F%282X%29+-+7%2Fx+=+0
now look in the current denominators and see what unique factors are there.
We have %28x%2B1%29 and 2x the other solitary x is already covered by the 2x.
So

%286x%5E2+%2B+6x%2B6+-+14x+-+14%29%2F%28%282x%29%2A%28x%2B1%29%29+=+0
%286x%5E2+-8x+-8%29%2F%28%282x%29%2A%28x%2B1%29%29+=+0
6x%5E2+-+8x+-+8 = 0
Use the quadratic equation to solve. Then check your answers to make sure that the values of x given do not make %28%282x%29%2A%28x%2B1%29%29 = 0 too