SOLUTION: Hello, this is the problem: The sum of two numbers is 4 less than twice the larger. If the larger is decreased by three times the smaller, the result is -20. Thank you

Algebra ->  Systems-of-equations -> SOLUTION: Hello, this is the problem: The sum of two numbers is 4 less than twice the larger. If the larger is decreased by three times the smaller, the result is -20. Thank you       Log On


   

Question 135700: Hello, this is the problem: The sum of two numbers is 4 less than twice the larger. If the larger is decreased by three times the smaller, the result is -20.
Thank you
Found 2 solutions by vleith, stanbon:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the smaller number and y be the larger one.
x+%2B+y+=+2y+-4
x+%2B+4+=+y
y+-+3x+=+-20 sub for y using the value above
%28x%2B4%29+-+3x+=+-20
+-2x+%2B+4+=+-20
+-2x+=+-24+
x+=+12
Which means y = 16
Check your answer. Is (12+16) = (32-4)??? yes it is!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of two numbers is 4 less than twice the larger. If the larger is decreased by three times the smaller, the result is -20.
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EQUATIONS:
x+y = 2x+4
x-3y = -20
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x= 3y-20
Substitute to get:
3y-20+y = 2(3y-20)+4
4x-20 = 6y-56
2y = 36 (the smaller number)
y = 18
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x = 3*18-20
x = 34 (the larger number)
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Cheers,
Stan H.
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