SOLUTION: When I move the varible x to the other side and I divide the 12 and -x by negative 6, I am confused. x-6y=12. I get -6y=12-x. I know that to isolate y I need to divide the -6 by al

Algebra ->  Linear-equations -> SOLUTION: When I move the varible x to the other side and I divide the 12 and -x by negative 6, I am confused. x-6y=12. I get -6y=12-x. I know that to isolate y I need to divide the -6 by al      Log On


   

Question 135533This question is from textbook Intro&IntermediateAlgebra
: When I move the varible x to the other side and I divide the 12 and -x by negative 6, I am confused. x-6y=12. I get -6y=12-x. I know that to isolate y I need to divide the -6 by all terms. But I don't understand the -x over -6 This question is from textbook Intro&IntermediateAlgebra

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given: x-6y=12
-6y=12+-+x
y+=+%2812-x%29%2F%28-6%29
y+=+%28%28-1%29%2812-x%29%29%2F%28%28-1%29%28-6%29%29+ remember(-1/-1) is just a multiply by 1
y+=+%28-12%2Bx%29%2F%286%29
y+=+%28x+-12%29%2F6+