SOLUTION: this problem comes from a teacher-made worksheet: {{{log((x-90)) = 3 - log((x))}}} x = 100,-10 -10 is an extraneous solution, so x = 100

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: this problem comes from a teacher-made worksheet: {{{log((x-90)) = 3 - log((x))}}} x = 100,-10 -10 is an extraneous solution, so x = 100      Log On


   

Question 135518: this problem comes from a teacher-made worksheet:
log%28%28x-90%29%29+=+3+-+log%28%28x%29%29
x = 100,-10
-10 is an extraneous solution, so x = 100
Answer by vleith(2983) About Me  (Show Source):