SOLUTION: The length of a rectangle is 1cm more than 4 times the width. The perimiter is 42cm. find the length and width let__=width let__=length equation solve

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 1cm more than 4 times the width. The perimiter is 42cm. find the length and width let__=width let__=length equation solve      Log On


   

Question 13546: The length of a rectangle is 1cm more than 4 times the width. The perimiter is 42cm. find the length and width
let__=width
let__=length
equation
solve
Answer by LilSkittleMd(119) About Me  (Show Source):
You can put this solution on YOUR website!
Let L equal length
Let W equal width
First you need to know the equation for the perimeter of a rectangle:
P=2L+2W
P=42
L=1+4W
Plug in the values for P and L in the appropriate places in the equation for perimeter:
42=2(1+4W)+2W
42=2+8W+2W
42=2+10W
40=10W
4=W
Now that you have found the value for W, plug it into one of the equations
L=1+4(4)
L=1+16
L=17
The length of the rectangle 17 cm and the width is 4 cm