SOLUTION: Three times the greatest of 3 consecutive even integers exceeds twice the least by 38. Find the integers.

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Question 135407: Three times the greatest of 3 consecutive even integers exceeds twice the least by 38. Find the integers.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X, X+2 & X+4 BE THE 3 INTEGERS.
3(X+4)-2X=38
3X+12-2X=38
X=38-12
X=26 ANSWER FOR THE SMALLEST INTEGER.
26+2=28 FOR THE MIDDLE INTEGER
26+4=30 IS THE LARGESTINTEGER.
PROOF:
3*30-2*26=38
90-52=38
38=38