SOLUTION: x^4-x^2-42=0
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Question 135317
:
x^4-x^2-42=0
Answer by
edjones(8007)
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x^4-x^2-42=0
(x^2-7)(x^2+6)=0
.
x^2=7
x=sqrt(7), x=-sqrt(7)
.
If you use imaginary numbers:
x^2=-6
x=sqrt(6)i, x=-sqrt(6)i
.
Ed