SOLUTION: Find the equation of each line in the form y = mx + b if possible. The line through the origin that is perpendicular to the line through (-3,0) and (0,-3)

Algebra ->  Graphs -> SOLUTION: Find the equation of each line in the form y = mx + b if possible. The line through the origin that is perpendicular to the line through (-3,0) and (0,-3)      Log On


   

Question 135020: Find the equation of each line in the form y = mx + b if possible.
The line through the origin that is perpendicular to the line through (-3,0) and (0,-3)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+mx+%2B+b is the general form of a straight line equation where
m= slope. You are given 2 points (-3,0) and (0,-3) on a line
For 1st point, substitute for y and x
0+=+m%2A%28-3%29+%2B+b
0+=+-3m+%2B+b
m+=+b%2F3
And the same for the 2nd point
-3+=+m%2A0+%2B+b
b+=+-3
and
m+=+b%2F3
m+=+-3%2F3
m+=+-1
So, the equation of the line through (-3,0) and (0,-3) is
y+=+-x+-+3
A line perpendicular to this line will have slope = -%281%2Fm%29+=+-%281%2F%28-1%29%29 so, slope = 1
What is the equation of the line through the origin with slope = 1?
In the formula y+=+mx+%2B+b, b is the y-intercept, and a line
through the origin has b+=+0
y+=+1%2Ax+%2B+0 or
y+=+x is the answer