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Question 134819: The given points are, A=(6,-8) B=(-2,-4)
Find the equation of line AB( general form), then find the y-intercept of AB
Answer by algebrapro18(249)   (Show Source):
You can put this solution on YOUR website! Well for starters you need to find the slope of the line. To find the slope you use the following formula:
m = (y2-y1)/(x2-x1) where
x1 = 6
y1 = -8
x2 = -2
y2 = -4
so plugging into the formula you get
m = (-4-(-8))/(-2-6)
m = (-4+8)/(-2-6)
m = 2/-8
m = -1/4
now you can find the general from of the line by finding the y-intercept of that line(b in y = mx + b):
y = mx + b
-4 = -1/4(-2) + b
-4 = 1/2 + b
-9/2 = b
Now we can put this into slope-intercept form
y = -1/4x - 9/2
From here you do a little math to get it into standard form. Standard form is ax + by = c where a, b, and c are all integers.
y = -1/4x - 9/2
4y = -x - 18
x + 4y = -18
we found the y-intercept earlier to be -9/2.
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