SOLUTION: I am having a hard time trying to solve this problem, if anyone could help me step by step, thank you. Power rule for integral exponents: (3y to the eighth power) divided by

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I am having a hard time trying to solve this problem, if anyone could help me step by step, thank you. Power rule for integral exponents: (3y to the eighth power) divided by       Log On


   

Question 134752: I am having a hard time trying to solve this problem, if anyone could help me step by step, thank you.
Power rule for integral exponents:
(3y to the eighth power) divided by (2zy to the second power)
Found 3 solutions by vleith, checkley77, josmiceli:
Answer by vleith(2983) About Me  (Show Source):
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
(3Y)^8/(2ZY)^2
6,561Y^8/4Z^2Y^2
6,561Y^(8-2)/4Z^2
6,561Y^6/4Z^2 ANSWER.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If I understand the problem, it is
%283y%29%5E8+%2F+%282zy%29%5E2
You can use the rule %28abc%29%5En+=+%28a%5En%29%2A%28b%5En%29%2A%28c%5En%29


%283%5E8%29%2A%28y%2A6%29+%2F+4z%5E2+=+6561y%5E6+%2F+4z%5E2