SOLUTION: log(x-2)+log(2x-3)=2Logx

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Question 134734: log(x-2)+log(2x-3)=2Logx
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given: log%28x-2%29%2Blog%282x-3%29=2Logx
10%5E%28log%28x-2%29%2Blog%282x-3%29%29=10%5E%282Logx%29+
10%5E%28log%28x-2%29%29%2A10%5E%28log%282x-3%29%29=10%5E%282Logx%29+
%28x-2%29%282x-3%29+=+x%5E2+
2x%5E2+-7x+%2B+6+=+x%5E2
x%5E2+-7x+%2B+6+=+0
%28x+-1%29%28x-6%29+=+0+
x = 1, 6 are possible solutions
Verify
Does Log(4) + Log(9) = 2*Log(6) ??
Does Log(-1) + Log(-1) = 2*Log(1) --> there is no such thing as a real number with a negative log, so 1 is not an answer.