SOLUTION: one number is 4 less than 3 times a second number. if 3 more than twice the first number is decreased by twice the second, the result is 11. find both numbers.

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Question 134616: one number is 4 less than 3 times a second number. if 3 more than twice the first number is decreased by twice the second, the result is 11. find both numbers.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the 1st number a
Call the 2nd number b
a+=+3b+-+4
2a+%2B+3+-+2b+=+11
Substitute a in the 1st for a in the 2nd
2%2A%283b+-+4%29+%2B+3+-+2b+=+11
6b+-+8+%2B+3+-+2b+=+11
4b+=+11+%2B+8+-+3
4b+=+16
b+=+4
a+=+3b+-+4
a+=+3%2A4+-+4
a+=+8
The numbers are 8 and 4
check:
2a+%2B+3+-+2b+=+11
2%2A8+%2B+3+-+2%2A4+=+11
19+-+8+=+11
11+=+11
a+=+3b+-+4
8+=+3%2A4+-+4
8+=+8
OK