You can put this solution on YOUR website! equation (1/5)^-6=15625 in logarithm form
log(base(1/5) 15625 = -6
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find the value of x log 2 32=x
2^x = 32
2^x = 2^5
x = 5
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express log (x+5) log as the logarithm of a single quanity
log(x+5) = log(x+5)
The log of a sum is simply the log of a sum.
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Cheers,
Stan H.
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