SOLUTION: Graph: {{{(x^2+6x+8)/(x^2-x-2)}}}
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-> SOLUTION: Graph: {{{(x^2+6x+8)/(x^2-x-2)}}}
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Question 13422
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Graph:
Answer by
rapaljer(4671)
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Notice that this factors into:
.
Consequently, there are roots at x= -4 and x=-2, and there are asymptotes at x= 2, and x=-1, since the function is UNDEFINED at x = 2 and x=-1. It may look as if the graph touches or crosses these asymptotes, but rest assured--IT DOES NOT!!
R^2 at SCC