Question 134131: Hello I am trying to find the solution to this problem about age. Im not sure if you divide or what steps you take to complete this problem.
I would think you divide 28 evenly...but i'm confused. Any help would be great!
Ralph is ten years older than his sister Rose. If the sum of their ages in three years is 28, how old are they now? Be sure to include all necessary work and the ages of each person.
Thank you very much for your time,
Mrs. Gibson
Answer by jojo14344(1513)   (Show Source):
You can put this solution on YOUR website! Let's assigned "x" = age of Rose at present
So, "x + 10" = age of Ralph at present
But in 3 years from now the sum of their ages will be 28.
So, we need to add 3 years on their present age and the sum will equal to 28.
To show that,
x+3 (age of Rose) + x+10+3 (age of Ralph) = 28 (equation 1)
2x+16=28
2x=28-16
x=6 This will be the age of Rose at present
For Ralph, x+10 = 16 age at present
To check 3 years from now, we go back to equation 1 above:
x+3+x+10+3=28
6+3+6+10+3=28
28=28
Very good!
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