SOLUTION: Anne is now seven times as old as joan.In six years ann will be five times as old as joan.find the age of each one. Let a=Anne's age j=Joan's age a = 7j now.----------- (1) In

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Anne is now seven times as old as joan.In six years ann will be five times as old as joan.find the age of each one. Let a=Anne's age j=Joan's age a = 7j now.----------- (1) In       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 134086: Anne is now seven times as old as joan.In six years ann will be five times as old as joan.find the age of each one.
Let a=Anne's age j=Joan's age
a = 7j now.------------(1)
In 6 yrs, a+6 =5(j+6)---(2)
(2)-(1): 6= 5(j+6)-6j==>
6=5j+30-7j =30-2j==>
j=24/2=12. Substitute j=12 in (1) to get a=7*12=84.
a= Anne's age=84 and j=joan's age =12

Answer by Ganesha(13) About Me  (Show Source):
You can put this solution on YOUR website!
Let a=Anne's age j=Joan's age
a = 7j now.------------(1)
In 6 yrs, a+6 =5(j+6)---(2)
(2)-(1): 6= 5(j+6)-6j==>
6=5j+30-7j =30-2j==>
j=24/2=12. Substitute j=12 in (1) to get a=7*12=84.
a= Anne's age=84 and j=joan's age =12