SOLUTION: for the pie chart 37 people picked juice A, 32 people picked juice B, and 21 people picked juice C.. so what is the probability that a person chosen at random chose juice B?

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Question 134002: for the pie chart 37 people picked juice A, 32 people picked juice B, and 21 people picked juice C..
so what is the probability that a person chosen at random chose juice B?
Found 2 solutions by vleith, andishmonkeygirl:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given: 37 are A, 32 are B and 21 are C.
The total peeople picking juice is +37+%2B+32+%2B+21 = 90
The probability of someone choosing juice B = +%28Number+choosing+B%29+%2F+%28Total%29+
+32+%2F+90+ = 16%2F45 or 16 out of 45

Answer by andishmonkeygirl(3) About Me  (Show Source):
You can put this solution on YOUR website!
first you add all of the numbers of people together so you get the total amount of people possible
37+32+21=90
then how many people picked juice b?
32
so you put that over the total amount of people
32/90
simplify the fraction
16/45