Question 133839: 7/ 3-5i
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website!
7/(3-5i) First, we'll multiply the numerator and denominator by the conjugate of 3-5i which is 3+5i. This will get rid of the radical in the denominator.
(7(3+5i))/((3-5i)(3+5i)) =
(7(3+5i))/(9-25(i^2)) but i^2 is -1, so
(7(3+5i))/(9+25)=
7(3+5i)/34
Hope this helps---ptaylor
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