SOLUTION: 2 [k-3(4-2k)] = 2(k-3) + 3 Can you plese help with this eqaution?

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Question 13370: 2 [k-3(4-2k)] = 2(k-3) + 3
Can you plese help with this eqaution?

Found 2 solutions by akmb1215, hyh_123:
Answer by akmb1215(68) About Me  (Show Source):
You can put this solution on YOUR website!
First of all, you need to do the distributive property as many times as necessary to get rid of parentheses. By doing this, you will get:
2%28k-12%2B6k%29=2k-6%2B3
2k-24%2B12k+=+2k-6%2B3
Now that you have that, add like terms to get 14k-24+=+2k-3.
Move everything with a k to one side of the equal sign and everything without a k to the other side of the equal sign to get 12k+=+21. Divide by 12 to get k=%2821%2F12%29.

Answer by hyh_123(8) About Me  (Show Source):
You can put this solution on YOUR website!
First open all the brackets (BODMAS)
You will have 2k-24+12k = 2k-6+3
Arrange the same terms together(e.g 2k+3k)
Now you will have 2k-2k+12k = 24-6=3
Cancel +2k with -2k
You will have 12k = 24-6+3
12k = 18+3
12k = 21
Divide 21 by 12
k =(21/12)