SOLUTION: Can you please help with this eqaution? Here what I've tried so far. 2 [k-3(4-2k)] = 2(k-3) + 3 2[k-3-4+2k]=2k-6+3 2k-6-8+4k=2k-6+3 6k-14=2k-3 6k-6k-14=2k-6k-3 14+3=-4k-

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Can you please help with this eqaution? Here what I've tried so far. 2 [k-3(4-2k)] = 2(k-3) + 3 2[k-3-4+2k]=2k-6+3 2k-6-8+4k=2k-6+3 6k-14=2k-3 6k-6k-14=2k-6k-3 14+3=-4k-      Log On


   

Question 13366: Can you please help with this eqaution?
Here what I've tried so far.
2 [k-3(4-2k)] = 2(k-3) + 3
2[k-3-4+2k]=2k-6+3
2k-6-8+4k=2k-6+3
6k-14=2k-3
6k-6k-14=2k-6k-3
14+3=-4k-3-14
17=-4k
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Here what I've tried so far.
2 [k-3(4-2k)] = 2(k-3) + 3

Your mistake is in the next step! You must multiply -3 times the 4 and times the -2k.
2[k-3-4+2k]=2k-6+3 Error in this step!

It should be this:
2[k-12 + 6k]= 2k - 6 + 3
2k - 24 + 12k = 2k - 3
14k - 24 = 2k - 3

Subtract 2k from each side:
14k - 2k - 24 = 2k - 2k - 3
12k - 24 = -3

Add 24 to each side:
12k - 24 + 24 = -3 + 24
12k = 21
k+=+21%2F12+=+7%2F4+

R^2 at SCC