Question 133476: 1. The cost, in millions of dollars, to remove x % of pollution in a lake
modeled by : C=6,000/200-2x
a. What is the cost to remove 75% of the pollutant?
b. What is the cost to remove 90 % of the pollutant?
c. What is the cost to remove 99% of the pollutant?
d. For what value is this equation undefined?
e. Do the answers to sections a–d match your expectations? Why or why not?
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! C=6,000/(200-2X)
C=6,000/(200-2*.75))
C=6,000/(200-1.5)
C=6,000/198.5
C=30.23 MILLION FOR 75% REMOVAL.
C=6,000/(200-2*.9)
C=6,000/200-1.8)
C=6,000/198.2
C=30.27 MILLION FOR 90% REMOVAL.
C=6,000/(200-2*.99)
C=6,000/(200-1.98)
C=6,000/198.02
C=30.30 MILLION FOR 99% REMOVAL.
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