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A certain amount of 8% solution must be added to another amount of a 5% salt solution to produce a total of 36 ounces of a 6% solution. How many ounces of each solution is needed?
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Answer by nycsharkman(136)   (Show Source):
You can put this solution on YOUR website! A certain amount of 8% solution must be added to another amount of a 5% salt solution to produce a total of 36 ounces of a 6% solution. How many ounces of each solution is needed?
We have a mixture problem here.
We have two mixtures that add up to 36 ounces of 6% salt solution.
The total is 36 ounces of 6%. This means that 6% is salt and the rest is NOT salt.
I will use brakets to separate the different mixture amounts.
Ready?
I do not know the amount of ounces for 8% solution. So, let's call that x (you can use any letter of choice).
[x(0.08)]...first mixture
If there are 36 ounces in total, then 36 MINUS x will yield the second mixture that we need to add to the first mixture.
[0.05(36 - x)]...second solution.
Are you will me so far?
The above two mixtures equal 36 times 0.06.
[x(0.08)] + [0.05(36 - x)] = 0.06(36)
We now solve for x.
0.08x + 1.8 - 0.05x = 2.16
0.08x - 0.05x = 2.16 - 1.8
0.03x = 0.36
x = 0.36/0.03
x = 12
How much of each, right?
For the 8% salt solution, there are 12 ounces.
For the 5% salt solution, there are 36 - 12 or 24 ounces.
Did you follow?
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