SOLUTION: Divide. Use synthetic division if possible (8x^4+5x^3+4x^2-x+7)/(x+1) (12x^3+31x^2-17x-6)/(x+3) i need some major help with these 2 questions. i was given 110 questions, i nee

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Divide. Use synthetic division if possible (8x^4+5x^3+4x^2-x+7)/(x+1) (12x^3+31x^2-17x-6)/(x+3) i need some major help with these 2 questions. i was given 110 questions, i nee      Log On


   



Question 133344: Divide. Use synthetic division if possible
(8x^4+5x^3+4x^2-x+7)/(x+1)
(12x^3+31x^2-17x-6)/(x+3)
i need some major help with these 2 questions. i was given 110 questions, i need some help with these 2=/

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 1


Let's simplify this expression using synthetic division


Start with the given expression %288x%5E4+%2B+5x%5E3+%2B+4x%5E2+-+x+%2B+7%29%2F%28x%2B1%29

First lets find our test zero:

x%2B1=0 Set the denominator x%2B1 equal to zero

x=-1 Solve for x.

so our test zero is -1


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
-1|854-17
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 8)
-1|854-17
|
8

Multiply -1 by 8 and place the product (which is -8) right underneath the second coefficient (which is 5)
-1|854-17
|-8
8

Add -8 and 5 to get -3. Place the sum right underneath -8.
-1|854-17
|-8
8-3

Multiply -1 by -3 and place the product (which is 3) right underneath the third coefficient (which is 4)
-1|854-17
|-83
8-3

Add 3 and 4 to get 7. Place the sum right underneath 3.
-1|854-17
|-83
8-37

Multiply -1 by 7 and place the product (which is -7) right underneath the fourth coefficient (which is -1)
-1|854-17
|-83-7
8-37

Add -7 and -1 to get -8. Place the sum right underneath -7.
-1|854-17
|-83-7
8-37-8

Multiply -1 by -8 and place the product (which is 8) right underneath the fifth coefficient (which is 7)
-1|854-17
|-83-78
8-37-8

Add 8 and 7 to get 15. Place the sum right underneath 8.
-1|854-17
|-83-78
8-37-815

Since the last column adds to 15, we have a remainder of 15. This means x%2B1 is not a factor of 8x%5E4+%2B+5x%5E3+%2B+4x%5E2+-+x+%2B+7
Now lets look at the bottom row of coefficients:

The first 4 coefficients (8,-3,7,-8) form the quotient

8x%5E3+-+3x%5E2+%2B+7x+-+8

and the last coefficient 15, is the remainder, which is placed over x%2B1 like this

15%2F%28x%2B1%29



Putting this altogether, we get:

8x%5E3+-+3x%5E2+%2B+7x+-+8%2B15%2F%28x%2B1%29

So

which looks like this in remainder form:
%288x%5E4+%2B+5x%5E3+%2B+4x%5E2+-+x+%2B+7%29%2F%28x%2B1%29=8x%5E3+-+3x%5E2+%2B+7x+-+8 remainder 15


You can use this online polynomial division calculator to check your work










# 2



Let's simplify this expression using synthetic division


Start with the given expression %2812x%5E3+%2B+31x%5E2+-+17x+-+6%29%2F%28x%2B3%29

First lets find our test zero:

x%2B3=0 Set the denominator x%2B3 equal to zero

x=-3 Solve for x.

so our test zero is -3


Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
-3|1231-17-6
|

Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 12)
-3|1231-17-6
|
12

Multiply -3 by 12 and place the product (which is -36) right underneath the second coefficient (which is 31)
-3|1231-17-6
|-36
12

Add -36 and 31 to get -5. Place the sum right underneath -36.
-3|1231-17-6
|-36
12-5

Multiply -3 by -5 and place the product (which is 15) right underneath the third coefficient (which is -17)
-3|1231-17-6
|-3615
12-5

Add 15 and -17 to get -2. Place the sum right underneath 15.
-3|1231-17-6
|-3615
12-5-2

Multiply -3 by -2 and place the product (which is 6) right underneath the fourth coefficient (which is -6)
-3|1231-17-6
|-36156
12-5-2

Add 6 and -6 to get 0. Place the sum right underneath 6.
-3|1231-17-6
|-36156
12-5-20

Since the last column adds to zero, we have a remainder of zero. This means x%2B3 is a factor of 12x%5E3+%2B+31x%5E2+-+17x+-+6

Now lets look at the bottom row of coefficients:

The first 3 coefficients (12,-5,-2) form the quotient

12x%5E2+-+5x+-+2


So %2812x%5E3+%2B+31x%5E2+-+17x+-+6%29%2F%28x%2B3%29=12x%5E2+-+5x+-+2

You can use this online polynomial division calculator to check your work