SOLUTION: Please find the unknown in the equation using steps log2 1056 = log2(2^a+5 plus 2^a) Please note that the 2 in the "log2 1056" is small

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please find the unknown in the equation using steps log2 1056 = log2(2^a+5 plus 2^a) Please note that the 2 in the "log2 1056" is small      Log On


   

Question 133340: Please find the unknown in the equation using steps
log2 1056 = log2(2^a+5 plus 2^a)
Please note that the 2 in the "log2 1056" is small
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given: log2 1056 = log2(2^a+5 plus 2^a)
So:
1056+=+2%5E%28a%2B5%29+%2B+2%5Ea+
1056+=+%282%5Ea%29%2A%282%5E5%29+%2B+2%5Ea
+1056+=+32+%282%5Ea%29+%2B+2%5Ea+
+1056+=+33+%282%5Ea%29+
+32+=+2%5Ea
a = 5