SOLUTION: Please solve using logs:2^2x+4 minus 2 to the power of 2x = 120 Please show steps Thanks again

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Question 133329: Please solve using logs:2^2x+4 minus 2 to the power of 2x = 120
Please show steps
Thanks again
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
2^(2x+4)=(2^2x)(2^4)=16(2^2x)

16(2^2x)-2^2x=15(2^2x)

15(2^2x)=120 __ dividing by 15 __ 2^2x=8 __ taking log base 2 __ log2(2^2x)=log2(8)

log2(2^2x)=log2(2^3) __ 2x=3