SOLUTION: Use logs (any base) to find the unknown: 2 to the power of 2x^2-3x = 2 to the power of x^2-2x + 12 ( there are two answers find both please. Use steps, I would appreciate it:)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Use logs (any base) to find the unknown: 2 to the power of 2x^2-3x = 2 to the power of x^2-2x + 12 ( there are two answers find both please. Use steps, I would appreciate it:)      Log On


   

Question 133327: Use logs (any base) to find the unknown: 2 to the power of 2x^2-3x = 2 to the power of x^2-2x + 12
( there are two answers find both please. Use steps, I would appreciate it:)
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
taking log base 2 __ 2x^2-3x=x^2-2x+12 __ subtracting x^2-2x+12 __ x^2-x-12=0

factoring __ (x-4)(x+3)=0

so x-4=0 and x+3=0