SOLUTION: Find the unknown in the equation log5(-2500) = log5(5^n+2 minus 5^n+3) (Note: In one of the steps, you will need to get rid of the minus sign in -2500)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Find the unknown in the equation log5(-2500) = log5(5^n+2 minus 5^n+3) (Note: In one of the steps, you will need to get rid of the minus sign in -2500)       Log On


   

Question 133319: Find the unknown in the equation log5(-2500) = log5(5^n+2 minus 5^n+3) (Note: In one of the steps, you will need to get rid of the minus sign in -2500)

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given: log5(-2500) = log5(5^n+2 minus 5^n+3)
So -2500+=+5%5E%28n%2B2%29+-+5%5E%28n%2B3%29+
-2500+=+5%5En+%2A+5%5E2+-+5%5En+%2A+5%5E3
-2500+=+25%2A+%285%5En%29+-125+%2A+%285%5En%29+
-2500+=+-100+%2A+%285%5En%29
25+=+5%5En
n = 2