SOLUTION: The area of a rectangle is 12a+6. Find two possible perimeters for the rectangle.

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Question 133097: The area of a rectangle is 12a+6. Find two possible perimeters for the rectangle.
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
12a+6= 2(6a+3) then one option is 2(2+6a+3)=12a+10
12a+6= 3(4a+2) then 2nd option is 2(3+4a+2)=8a+10