SOLUTION: The distance traveled h(in meters) by an object thrown downward after t seconds is given by h=5t^2+Vot where Vo is the inital downward speed (in meters per second, m/s). If and

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Question 133090This question is from textbook INTERMEDIATE ALGEBRA
: The distance traveled h(in meters) by an object thrown downward after t seconds is given by h=5t^2+Vot
where Vo is the inital downward speed (in meters per second, m/s). If and object is thrown downward with an initial speed of 25 m/s from a height of 250 meters, how long does it take the object to hit the ground? This question is from textbook INTERMEDIATE ALGEBRA

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Given: h=5t%5E2%2BVot
We are given an initial height of 250M and and an initial velocity of 25.
So the question is, how long does it take to go 250 meters?
h=5t%5E2%2BVot
250=5t%5E2%2B25t
0+=+5t%5E2+%2B+25t+-+250
0+=+t%5E2+%2B+5t+-50
0+=+%28t+%2B10%29+%28t+-5%29
Setting each factor equal to o yields t = -10 AND t = 5.
Since time can't be negative, the answer must be 5 seconds.
Check you answer.
h=5t%5E2%2B25t
h=5%285%29%5E2%2B25%285%29
h+=+125+%2B+125 = 250 which is the total distance to the ground