SOLUTION: Find the x and y intercepts of the equation. x^2 + 8x +12 = 0

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Question 132740This question is from textbook Algebra & Trigono,etry
: Find the x and y intercepts of the equation.
x^2 + 8x +12 = 0
This question is from textbook Algebra & Trigono,etry

Answer by solver91311(24713) About Me  (Show Source):
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The equation, as you presented it, doesn't have any "intercepts." This quadratic equation has two solutions or roots that would be the x-intercepts of the function y+=+f%28x%29+=x%5E2+%2B+8x+%2B12. This function would also have a y-intercept at (0,f(0)).

If you meant to ask for the x-intercepts of y+=+f%28x%29+=x%5E2+%2B+8x+%2B12, then the method to find them consists of setting the function equal to 0, resulting in the equation you provided, and then solving for x.

x%5E2+%2B+8x+%2B12+=+0

6 * 2 = 12 and 6 + 2 = 8, so:

%28x%2B6%29%28x%2B2%29=0, therefore x = -6 or x = -2, and the x-intercepts of y+=+f%28x%29+=x%5E2+%2B+8x+%2B12 are the two points denoted by the ordered pairs (-6,0) and (-2,0).

As previously discussed the y-intercept of y+=+f%28x%29+=x%5E2+%2B+8x+%2B12 is at the point (0,f(0)). f%280%29+=0%5E2+%2B+8%280%29+%2B12=12, so the y-intercept is at the point (0,12).