SOLUTION: How would you solve this equation? 6/m-5-3/m+5=15/m^2-5

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Question 132696: How would you solve this equation?
6/m-5-3/m+5=15/m^2-5
Answer by TakeATuition.com(57) About Me  (Show Source):
You can put this solution on YOUR website!
++6%2F%28m-5%29+-++3%2F%28m%2B5%29+=+15%2F%28%28m%29%5E2-5%29
+%286%28m%2B5%29-3%28m-5%29%29%2F%28%28m-5%29%28m%2B5%29%29+=+15%2F%28%28m%29%5E2-5%29 Taking LCM
+%286m%2B30-3m%2B15%29%2F%28m%5E2-5%29+=+15%2F%28%28m%29%5E2-5%29
+%283m%2B45%29+=+%2815+%28m%5E2-5%29%29%2F%28%28m%29%5E2-5%29 cancel (m^2-5) in numrator and denomenator on Right hand side
3m + 45 = 15
3m = -45 +15
3m = -30
m = -10