SOLUTION: 2x^2+9x-5=0
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Question 132677
:
2x^2+9x-5=0
Answer by
stanbon(75887)
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2x^2+9x-5=0
Using the AC Method of factoring, you get:
2x^2+10x-x-5 = 0
2x(x+5)-(x+5) = 0
(x+5)(2x-1) = 0
x = -5 or x = 1/2
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Cheers,
Stan H.