SOLUTION: A rectangle garden has dimensions of 18 feet by 13 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 516 s

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A rectangle garden has dimensions of 18 feet by 13 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 516 s      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 132411: A rectangle garden has dimensions of 18 feet by 13 feet. A gravel path of equal width is to be built around the garden. How wide can the path be if there is enough gravel for 516 square feet?
Found 2 solutions by checkley71, edjones:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(18+2X)(13+2X)-18*13=516
234+26X+36X+4X^2-234=516
4X^2+62X-516=0
(2X+43)(2X-12)=0
2X-12=0
2X=12
X=12/2
X=6 FT. ANSWER FOR THE WIDTH OF THE PATH.
(18+2*6)(13+2*6)-234=516
(18+12)(13+12)-234=516
30*25-234=516
750-234=516
516=516

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
L*w=A
18*13=234 ft^2
Let x=width of the path
(x+18)(x+13)-234=516
x^2+31x+234-234=516
x^2+31x-516=0
(x+43)(x-12)=0
x=12 ft.
.
Ed