SOLUTION: if y varies directly as to the square of x and inversely as z and y=40 when x=2 and z=1/2. Find y when x=3 and z=9
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Question 132205: if y varies directly as to the square of x and inversely as z and y=40 when x=2 and z=1/2. Find y when x=3 and z=9 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! if y varies directly as to the square of x and inversely as z and y=40 when x=2 and z=1/2. Find y when x=3 and z=9
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y = kx^2/z
Find "k":
40 =k(2^2)/(1/2)
20 = 4k
k = 5
EQUATION:
y = 5x^2/z
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Find y when x=3 and z=9
y = 5*(3^2)/9
y = 5
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Cheers,
Stan H.
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