SOLUTION: A coin bank contains nickels, dimes and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the b

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Question 132038This question is from textbook Holt Algebra 1
: A coin bank contains nickels, dimes and quarters totaling $5.45. If there are twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank? I figured out the answer but am having a problem with the formula.
Thanks This question is from textbook Holt Algebra 1

Answer by solver91311(24713) About Me  (Show Source):
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Number of nickels: n
Number of dimes: d
Number of quarters: q

Value of the nickels: 5n cents
Value of the dimes: 10d cents
Value of the quarters: 25q cents

Total money: $5.45, but express it as 545 cents.

Twice as many quarters as dimes:
q = 2d or d = q/2

11 more nickels than quarters:
n = q + 11

Total value equation:
5n + 10d + 25q = 545

Substitute for n and d
5(q + 11) + 10(q/2) + 25q = 545

You should be able to take it from there.