SOLUTION: Can you help me with this problem? Again, I am having touble with the common denominator. (4y/y^2+6y+5)+(2y/y^2-1) Thanks!

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Question 132000: Can you help me with this problem? Again, I am having touble with the common denominator.
(4y/y^2+6y+5)+(2y/y^2-1)
Thanks!
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
(4y/y^2+6y+5)+(2y/y^2-1)
%284y%29%2F%28%28y%2B5%29%28y%2B1%29%29+%2B+%282y%29%2F%28%28y-1%29%28y%2B1%29%29+

The LCD = %28y%2B5%29%28y%2B1%29%28y-1%29



Combine numerators:



+%284y%5E2-4y%2B2y%5E2%2B10y%29%2F%28%28y%2B5%29%28y%2B1%29%28y-1%29%29+

%286y%5E2%2B6y%29%2F%28%28y%2B5%29%28y%2B1%29%28y-1%29%29+

%286y%28y%2B1%29%29%2F%28%28y%2B5%29%28y%2B1%29%28y-1%29%29+

Reduce the fraction:
%286y%29%2F%28%28y%2B5%29%28y-1%29%29+

Nice Problem!!!

For additional help with common denominators and adding fractions like this, please see my website by clicking on my tutor name "rapaljer" anywhere in algebra.com. Click on the first link on my homepage which is "Basic and Intermediate Algebra: One Step at a Time." Go to Chapter 3 in Basic Algebra, and click on Sections 3.03 and 3.04. Section 3.04 has a much simpler explanation on this type of problem than most books. See also my MATH IN LIVING COLOR pages in Basic Algebra Chapter 3 that relate to this topic!!

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