SOLUTION: I have no idea where to start.
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Find a polynomial for the perimeter and for the area.
a+9 is along the horizontal top of the square and a is on the right vertical side
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-> SOLUTION: I have no idea where to start.
Thank You
Find a polynomial for the perimeter and for the area.
a+9 is along the horizontal top of the square and a is on the right vertical side
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Question 131868: I have no idea where to start.
Thank You
Find a polynomial for the perimeter and for the area.
a+9 is along the horizontal top of the square and a is on the right vertical side of the square
The perimeter is...........
The area is......... Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Find a polynomial for the perimeter and for the area of the figure.
The problem says "square" but one side (the base) is given as 9+a and another side (the height) is given as a. It can't be a square, so presumably, it's a rectangle whose length (L) is 9a and whose width (W) is a.
The perimeter of a rectangle is:
P = 2L+2W Substitute the given values for L (9a) and for W (a):
P = 2(9a)+2(a) Simplify.
P= 18a+2a This is a polynomial for the perimeter.
The area of a rectangle is:
A = L*W Substitute the given values for L (9a) and for W (a):
A = (9a)(a) Simplify. This is not a polynomial but a monomial.
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