SOLUTION: Can someone please help me with this. I am asked to write a quadractic equation having the given numbers as solutions. -6 and -3. I am not even sure where to start here. Thank you

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Question 131736: Can someone please help me with this. I am asked to write a quadractic equation having the given numbers as solutions. -6 and -3. I am not even sure where to start here. Thank you in advance.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
For solutions to ax%5E2+%2B+bx+%2B+c+=+0 you have
x+=+-6 and x+=+-3
x+-%28-6%29+=+0
x+-%28-3%29+=+0
x+%2B+6+=+0
x+%2B+3+=+0
If you multiply these, the result is
%28x+%2B+6%29%28x+%2B+3%29+=+x%5E2+%2B+9x+%2B+18
y+=+x%5E2+%2B+9x+%2B+18 answer
check:
Does x+=+-6 and x+=+-3 give me y+=+0?
y+=+%28-6%29%5E2+%2B+9%2A%28-6%29+%2B+18
y+=+36+-+54+%2B+18
y+=+0
y+=+%28-3%29%5E2+%2B+9%2A%28-3%29+%2B+18
y+=+9+-+27+%2B+18
y+=+0
OK