SOLUTION: In a 6-mile run, Cindy finished 15 minutes ahead of Bill. Cindys speed was 2 miles per hour faster than Bills speed. What was Bills speed?

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Question 131349: In a 6-mile run, Cindy finished 15 minutes ahead of Bill. Cindys speed was 2 miles per hour faster than Bills speed. What was Bills speed?
Found 2 solutions by checkley71, josmiceli:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
6/(x+2)+.25=6/x
[6+.25(x+2)]/(x+2)=6/x
[6+.25x+.5]/(x+2)=6/x
(6.5+.25x)/(x+2)=6/x
x(6.5+.25x)=6(x+2)
6.5x+.25x^2=6x+12
.25x^2+6.5x-6x-12=0
.25x+.5x-12=0
(.25x+2)(x-6)=0
x-6=0
x=6 mph is Bill's speed.
6+2=8 Cindy's speed.
proof
6/8+.25=6/6
.75+.25=1
1=1

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
d=distance in mi
r=rate in mi/hr
t=time in hours
d+=+r%2At
write an equation for both of them
d%5Bc%5D+=+r%5Bc%5D%2At%5Bc%5D This is Cindy's equation
d%5Bb%5D+=+r%5Bb%5D%2At%5Bb%5D This is Bill's equation
d%5Bc%5D+=+d%5Bb%5D They ran the same distance, d+=+6mi.
t%5Bc%5D+=+t%5Bb%5D+-+.25
r%5Bc%5D+=+r%5Bb%5D+%2B+2
d%5Bc%5D+=+r%5Bc%5D%2At%5Bc%5D
6+=+%28r%5Bb%5D+%2B+2%29%28t%5Bb%5D+-+.25%29
r%5Bb%5D%2At%5Bb%5D+=+6
t%5Bb%5D+=+6%2Fr%5Bb%5D
6+=+%28r%5Bb%5D+%2B+2%29%28%286%2Fr%5Bb%5D%29+-+.25%29
6+=+6+%2B+%2812%2Fr%5Bb%5D%29+-+.25%2Ar%5Bb%5D+-+.5
%2812%2Fr%5Bb%5D%29+-+.25%2Ar%5Bb%5D+-+.5+=+0
multiply both sides by r%5Bb%5D
12+-+.25%2A%28r%5Bb%5D%29%5E2+-+.5%2Ar%5Bb%5D+=+0
.25%2A%28r%5Bb%5D%29%5E2+%2B+.5%2Ar%5Bb%5D+-+12+=+0
multiply both sides by 4
r%5Bb%5D%5E2+%2B+2%2Ar%5Bb%5D+-+48+=+0
Solve by completing the square
r%5Bb%5D%5E2+%2B+2%2Ar%5Bb%5D+%2B+1+=+48+%2B+1
%28r%5Bb%5D+%2B+1%29%5E2+=+49
r%5Bb%5D+%2B+1+=+7 only the + root makes sense here
r%5Bb%5D+=+6 mi/hr answer
check answer:
6+=+r%5Bb%5D%2At%5Bb%5D
6+=+6%2A%28t%5Bb%5D%29
t%5Bb%5D+=+1 hr
r%5Bc%5D+=+r%5Bb%5D+%2B+2
r%5Bc%5D+=+8mi/hr
t%5Bc%5D+=+t%5Bb%5D+-+.25
t%5Bc%5D+=+1+-+.25
t%5Bc%5D+=+.75hr
6+=+r%5Bc%5D%2At%5Bc%5D
6+=+8%2A.75
6+=+6
OK