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| Question 131327:  Please Help!
 Determine the mean, median, mode, and midrange of the set of data.  Round your answer to the nearest tenth.
 a)  7,5,8,8,8,10,12
 b) 1,1,1,1,4,4,4,4,6,8,10,12,15,21
 The mean represents the average or the sum of the data divided by the number of pieces of data
 The median is the value in the middle of a set of ranked data
 The mode is the piece of date that occurs most frequently
 The midrange is the value half way between the lowest and highest
 values in a set of data.  It is found by adding the loweast and highest values and dividing the sum by 2.
 This is all I have been able to figure out about this problem-please help me piece it together!
 Thank you in advance
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Determine the mean, median, mode, and midrange of the set of data. Round your answer to the nearest tenth. ==============================
 a) 7,5,8,8,8,10,12
 The mean represents the average or the sum of the data divided by the number of pieces of data : mean = 58/7 = 8.2857
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 The median is the value in the middle of a set of ranked data
 median = 8
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 The mode is the piece of date that occurs most frequently
 mode = 8
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 The midrange is the value half way between the lowest and highest
 values in a set of data. It is found by adding the loweast and highest values and dividing the sum by 2.
 midrange = (5+12)/2 = 8.5
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 b) 1,1,1,1,4,4,4,4,6,8,10,12,15,21
 The mean represents the average or the sum of the data divided by the number of pieces of data
 mean = 92/14 = 6.57...
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 The median is the value in the middle of a set of ranked data
 median = 4
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 The mode is the piece of date that occurs most frequently
 You have two modes: 1 and 4 ; the data is said to be bimodal
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 The midrange is the value half way between the lowest and highest
 values in a set of data. It is found by adding the loweast and highest values and dividing the sum by 2.
 midrante = (1+21)/2 = 11
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 Cheers,
 Stan H.
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