SOLUTION: Hawaiiain punch is 10% fruit juice. How much water would you have to add to one gallon of hawaiiain punch to get a drink that is 6% fruit juice? my homework is 1 thru 41 odd

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: Hawaiiain punch is 10% fruit juice. How much water would you have to add to one gallon of hawaiiain punch to get a drink that is 6% fruit juice? my homework is 1 thru 41 odd      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 131154This question is from textbook elementry algebra
:
Hawaiiain punch is 10% fruit juice. How much water would you have to add to one gallon of hawaiiain punch to get a drink that is 6% fruit juice?
my homework is 1 thru 41 odd, been able to solve all but #39. on the above I cannot figure out how to set it up. Thank you in advance for any help
This question is from textbook elementry algebra

Found 2 solutions by Edwin McCravy, checkley71:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Hawaiiain punch is 10% fruit juice. How much water would you have to add to one gallon of hawaiiain punch to get a drink that is 6% fruit juice?
my homework is 1 thru 41 odd, been able to solve all but #39. on the above I cannot figure out how to set it up. Thank you in advance for any help

First I'll give you the answer and check it. Then I'll tell
you how I got it.  The reason I do it this way is to show
you that it takes the exact same thinking to check a word
problem, starting with the answer, as it does to set up the
equation, starting with x.  You'll see.

The answer: You would have to add 2%2F3 of a gallon of water.

Checking using the answer 2%2F3 gallon of water.

We have 1 gallon of Hawaiian punch to begin with.
10% of 1 gallon is 1%2F10 gallon of fruit juice.
Suppose we add 2%2F3 gallon of water.  We will then
have 1%2B2%2F3 or 5%2F3 gallons of liquid of
which 1%2F10 gallon is fruit juice, so

%28amt_of_fruit_juice%29%2F%28amt_of_liquid%29 equals .06

because %281%2F10%29%2F%285%2F3%29 = %281%2F10%29%283%2F5%29 = 3%2F50 = .06

------------------------------------------

Now if you understand that, we will now "check it" using x gallon:

"Checking" using x gallon of water.

We have 1 gallon of Hawaiian punch to begin with.
10% of 1 gallon is 1%2F10 gallon of fruit juice.
Suppose we add x gallon of water.  We will then
have 1%2Bx gallons of liquid of
which 1%2F10 gallon is fruit juice, so

%28amt_of_fruit_juice%29%2F%28amt_of_liquid%29 equals .06

or

%281%2F10%29%2F%281%2Bx%29 = .06

Multiply both sides by %281%2Bx%29

1%2F10 = .06%281%2Bx%29

Multiply both sides by 10

1 = .6%281%2Bx%29

Multiply both sides by 10

10 = 6%281%2Bx%29

10 = 6%2B6x

Subtract 6 from both sides:

4 = 6x

Divide both sides by 6

4%2F6 = %286x%29%2F6

Simplifying:

2%2F3 = x

Edwin

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
.06X=.1
X=.1/.06
X=1.6667 GALLONS OF 6% JUICE.
THUS .6667 GALLONS OF WATER NEEDS TO BE ADDED.