SOLUTION: George weighs 60 lbs. more than 1/2 his younger brother Galen's weight. If their weights balance when George is 4 ft. from the fulcrum on a 10 ft. long teeterboard, what are their

Algebra ->  Expressions-with-variables -> SOLUTION: George weighs 60 lbs. more than 1/2 his younger brother Galen's weight. If their weights balance when George is 4 ft. from the fulcrum on a 10 ft. long teeterboard, what are their       Log On


   



Question 130930: George weighs 60 lbs. more than 1/2 his younger brother Galen's weight. If their weights balance when George is 4 ft. from the fulcrum on a 10 ft. long teeterboard, what are their weights?




Found 2 solutions by stanbon, MaxW:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
George weighs 60 lbs. more than 1/2 his younger brother Galen's weight. If their weights balance when George is 4 ft. from the fulcrum on a 10 ft. long teeterboard, what are their weights?
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Let his brother's weight be "x" lbs. ; George = (x/2) + 60
EQUATION:
4[(x/2) + 60] = 10x
2x + 240 = 10x
8x = 240
x = 30 lbs : brother's weight
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(x/2) + 60 = 75 lbs. :George's weight
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Cheers,
Stan H.

Answer by MaxW(2) About Me  (Show Source):
You can put this solution on YOUR website!
using the equation d1(w1) = d2(w2)
4(1/2(x)+60) = 6x
2x + 240 = 6x subtract 2x from both sides
240 = 4x divide both sides by 4
x is equal to 60 lbs
Now plug 60 into Georg0e's weight equation:
(1/2(60) + 60
30 + 60 = 90 lbs
Therefore Galen is 60 lbs and George is 90 lbs.