You can put this solution on YOUR website! Find the value for n for which the sum 1+3+9+...to n terms is 364
---------
It's a geometric series with r = 3 and a(1) = 1
------------------
S(n) = a(1)[r^(n+1) - 1]/[r - 1]
364 = 1[3^(n+1) - 1] /2
3^(n+1) -1 = 728
3^(n+1) = 729
(n+1)log3 = log729
n+1 = log729/log3
n+1 = 6
n = 5
===========
Cheers,
Stan H.
(