SOLUTION: A MAN IS FOUR TIMES AS OLD AS HIS SON NOW. SIX YEARS AGO, HE WAS 7 TIMES AS OLD AS HIS SON DURING THAT TIME. FIND THEIR PRESENT AGES. THANK YOU VERY MUCH...
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: A MAN IS FOUR TIMES AS OLD AS HIS SON NOW. SIX YEARS AGO, HE WAS 7 TIMES AS OLD AS HIS SON DURING THAT TIME. FIND THEIR PRESENT AGES. THANK YOU VERY MUCH... This question is from textbook
You can put this solution on YOUR website! A MAN IS FOUR TIMES AS OLD AS HIS SON NOW. SIX YEARS AGO, HE WAS 7 TIMES AS OLD AS HIS SON DURING THAT TIME. FIND THEIR PRESENT AGES. THANK YOU VERY MUCH...
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NOW DATA:
Let his son's age be "x" ; Father's age is "4x"
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6 yrs. ago DATA:
Son is "x-6" ; Father is "4x-6"
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EQUATION:
4x-6 = 7(x-6)
4x-6 = 7x-42
3x = 36
x = 12 yrs old (son's age NOW)
4x= 48 yrs old (father's age NOW)
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Cheers,
Stan H.
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