SOLUTION: I need to find all the real values of x that satisfy the equation:
√(3-x) + √(3+x) = x
when you square both sides you get
6+2√(9-x^2)=x^2
I know that I m
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-> SOLUTION: I need to find all the real values of x that satisfy the equation:
√(3-x) + √(3+x) = x
when you square both sides you get
6+2√(9-x^2)=x^2
I know that I m
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Question 130831: I need to find all the real values of x that satisfy the equation:
√(3-x) + √(3+x) = x
when you square both sides you get
6+2√(9-x^2)=x^2
I know that I must square both sides again, but i think i'm squaring wrong.
Thank you! Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website! So far, you are ok. Add -6 to both sides before you square again. You will end up with the quartic: , but there is an x in every term, so one of the roots is 0. For the other three you will have to solve the cubic: . My advice: Google 'cubic solver' The first thing that comes up is a thing to plug in the coefficients and solve it. It also has a link to a description of how it works -- but unless you plan to stay up all night...
