SOLUTION: Solve for x: {{{3+e^(5x-1)=9}}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solve for x: {{{3+e^(5x-1)=9}}}       Log On


   



Question 130629: Solve for x: 3%2Be%5E%285x-1%29=9
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3%2Be%5E%285x-1%29=9 Start with the given equation


e%5E%285x-1%29=6 Subtract 3 from both sides


5x-1=ln%286%29 Take the natural log of both sides. This will eliminate the constant "e"


5x=ln%286%29%2B1 Add 1 to both sides


x=%28ln%286%29%2B1%29%2F5 Divide both sides by 5 to isolate x