SOLUTION: Ona canoe trip down the Spoon River, Jim is able to travel 10 miles downstream with the current in 2.5 hours. On the return trip upstream back to where his truck is parked, it tak

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Question 130540: Ona canoe trip down the Spoon River, Jim is able to travel 10 miles downstream with the current in 2.5 hours. On the return trip upstream back to where his truck is parked, it takes Jim 3.5 hours How fast is Jim's canoe traveling, and how fast is the current on the river at that day?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
10/2.5=R1
10/3.5=R2
R1=4 MPH WITH THE CURRENT
R2=2.857 MPH AGAINST THE CURRENT
4-2.857=1.14/2=.57 MPH FOR THE CURRENT.
PROOF
4-.57=2.857+.57
3.43=3.43