Question 130513: Question 1
Find the value of x for the following logarithm functions:
a) log2 16^x + log2 8 = -½
b) log3 x^2 + log3 4 = log 1
QUESTION 2
The revenue function of a company is R = 36q – 2q², where p represent the price per unit of the good and q represent the quantity demanded. Find the maximum value of the revenue for the revenue function given
QUESTION 3
The intersection point between two straight lines is (3,0), where the slope is given as below:
M1 = -2 dan M2 = 1
Find the equation for each of the two straight lines.
QUESTION 4
Find the average total profit if total revenue function is R(x) = x^2 – 50x and total cost function is C(x) = 100 – 30x
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The intersection point between two straight lines is (3,0), where the slope is given as below:
M1 = -2 and M2 = 1
Find the equation for each of the two straight lines.
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Line form: y = mx + b
If m1 = -2 and the line passes thru (3,0)
0 = -2*3 + b
b = 6
EQUATION is y = -2x + 6
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If m2 = 1 and the line passes thru (3,0),
0 = 1*3+b
b = -3
EQUATION is y = x -3
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QUESTION 4
Find the average total profit if total revenue function is R(x) = x^2 – 50x and total cost function is C(x) = 100 – 30x
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Profit = Revenue - Cost
Profit = x^2-50x - (100-30x)
P(x) = x^2-20x-100
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Cheers,
Stan H.
The revenue function of a company is R = 36q – 2q², where p represent the price per unit of the good and q represent the quantity demanded. Find the maximum value of the revenue for the revenue function given.
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Max occurs where q = -b/2a = -36/2*-2 = 9
R(9) = 36*9-2*9^2 = 162
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QUESTION 5
Find the value of x for the following logarithm functions:
a) log2 16^x + log2 8 = -½
log2 2^4x + log3 2^3 =
4x+3 = -1/2
8x+6 = = -1
8x = -7
x = -7/8
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b) log3 x^2 + log3 4 = log3 1
log2 [4x^2] = log3 1
4x^2 = 1
x^2 = 1/4
x = 1/2 or x = -1/2
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