SOLUTION: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now?

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Question 130494: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now?
Found 2 solutions by edjones, stanbon:
Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website!
Let k= Katie's age now, a= Anne's age now.
k-4=2(a-4)
k-4=2a-8
k-2a=-4
.
k=a+6
.
a+6-2a=-4 Substitute a+6 for k in the 1st equation.
-a=-10
a=10 y.o.
k=10+6=16 y.o.
.
Ed

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that Katie is now. How old is each now?
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Four yrs. ago DATA:
Let Anne's age be "x" yrs. old : Katie's age was was "2x" yrs.
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In 6 years DATA: (10 years after 4 years ago)
Anne will be "x+10" yrs old ; Katie will be "2x+10" yrs old.
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Now DATA: (4 years after 4 years ago)
Anne's age is "x+4" years ; Katie's age is "2x+4" years.
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EQUATION:
x+10 = 2x+4
x = 6
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NOW Ages:
Anne's age = x+4 = 6+4 = 10 years
Katie's age = 2x+4 = 2*6+4 = 16 years
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Cheers,
Stan H.